If $Z = \frac{A^{2} B^{3}}{C^{4}}$,then the relative error in $Z$ will be

  • A
    $\frac{\Delta A}{A} + \frac{\Delta B}{B} + \frac{\Delta C}{C}$
  • B
    $\frac{2 \Delta A}{A} + \frac{3 \Delta B}{B} - \frac{4 \Delta C}{C}$
  • C
    $\frac{2 \Delta A}{A} + \frac{3 \Delta B}{B} + \frac{4 \Delta C}{C}$
  • D
    $\frac{\Delta A}{A} + \frac{\Delta B}{B} - \frac{\Delta C}{C}$

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