જો $y=\tan ^{-1}\left\{\frac{a \cos x-b \sin x}{b \cos x+a \sin x}\right\}$ હોય,તો $\frac{d y}{d x}$ શોધો.

  • A
    $1$
  • B
    $0$
  • C
    $-1$
  • D
    $\frac{a}{b}$

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$\frac{d}{dx} \tan^{-1} \left[ \frac{\cos x - \sin x}{\cos x + \sin x} \right] = $

ધારો કે $f: R \rightarrow R$ એક સતત વિધેય છે. જો $px+my+n=0$ એ વક્ર $y=f(x)$ પર $x=\alpha$ આગળ દોરેલ સ્પર્શક હોય,તો $x=0$ આગળ $\frac{d}{d x}\left(f\left(\alpha e^{2 x}\right)\right)=$

$-1 < x < 1$ માટે $\tan ^{-1} x$ ની સાપેક્ષે $\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)$ નું વિકલન શું થાય?

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