यदि $4 \sin ^{-1} x + \cos ^{-1} x = \pi$ है,तो $x = $

  • A
    $\frac{\sqrt{3}}{2}$
  • B
    $0$
  • C
    $\frac{1}{2}$
  • D
    $\frac{1}{\sqrt{2}}$

Explore More

Similar Questions

श्रेणी $\tan^{-1}\left(\frac{1}{3}\right) + \tan^{-1}\left(\frac{2}{9}\right) + \dots + \tan^{-1}\left(\frac{2^{n-1}}{1+2^{2n-1}}\right) + \dots$ के अनंत पदों का योग ज्ञात कीजिए।

यदि $\sin ^{-1}\left(\frac{x}{5}\right)+\operatorname{cosec}^{-1}\left(\frac{5}{4}\right)=\frac{\pi}{2}$ है,तो $x$ का मान ज्ञात कीजिए।

$\sin ^{-1}\left(\cos \frac{\pi}{13}\right)+\cos ^{-1}\left(\sin \frac{\pi}{13}\right) = $ . . . . . . .

$\tan ^{-1}\left[\frac{1}{\sqrt{3}} \sin \frac{5 \pi}{2}\right] + \sin ^{-1}\left[\cos \left(\sin ^{-1} \frac{\sqrt{3}}{2}\right)\right]$ का मान ज्ञात कीजिए।

यदि $0 < x < \frac{1}{2}$ के लिए $y = 2\sin^{-1} \sqrt{1-x} + \sin^{-1} (2\sqrt{x(1-x)})$ है,तो $\frac{dy}{dx}$ का मान ज्ञात कीजिए।

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo