If $\sin \left(\sin ^{-1} \frac{1}{5}+\cos ^{-1} x\right)=1$,then the value of $x$ is

  • A
    $\frac{\pi}{2}+\frac{1}{5}$
  • B
    $\frac{\pi}{2}-\frac{1}{5}$
  • C
    $-\frac{1}{5}$
  • D
    $\frac{1}{5}$

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