Class 11MathematicsTrigonometrical EquationsRelation between sides and angles, Solutions of triangles
EasyIf $R$ is the circumradius of $\triangle ABC$,then the area of $\triangle ABC$ is equal to $\ldots$.
- A$\frac{abc}{R}$
- B$\frac{abc}{4R}$
- C$\frac{abc}{3R}$
- D$\frac{abc}{2R}$
Explore More
Similar Questions
In a $\Delta ABC$,the expression $\frac{\cos C + \cos A}{c + a} + \frac{\cos B}{b}$ is equal to:
Easy
View SolutionIf the angles of a triangle are in the ratio $4:1:1$,then the ratio of the longest side to its perimeter is
In $\triangle ABC$, with usual notations, if the sides $a, b$ and $c$ are in the ratio $18 : 17 : 7$, then $\cot \frac{A}{2} : \cot \frac{B}{2} : \cot \frac{C}{2} = $
DifficultMHT CET 2026
View SolutionIf the angles $A, B$ and $C$ of a triangle $ABC$ are in the ratio $2:3:7$ respectively,then the sides $a, b$ and $c$ are respectively in the ratio
In a $\Delta ABC$,$a, b, A$ are given and $c_1, c_2$ are two values of the third side $c$. The sum of the areas of the two triangles with sides $(a, b, c_1)$ and $(a, b, c_2)$ is
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo