यदि $\sin x + \sin^2 x = 1$ है,तो $\cos^8 x + 2\cos^6 x + \cos^4 x = $

  • A
    $0$
  • B
    $-1$
  • C
    $2$
  • D
    $1$

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मान लीजिए $\frac{\pi}{2} < \theta < \pi$ और $\cot \theta = -\frac{1}{2 \sqrt{2}}$ है। तब $\sin (\frac{15 \theta}{2}) (\cos 8 \theta + \sin 8 \theta) + \cos (\frac{15 \theta}{2}) (\cos 8 \theta - \sin 8 \theta)$ का मान ज्ञात कीजिए:

$\cos ^2 5^{\circ}-\cos ^2 15^{\circ}-\sin ^2 15^{\circ}+\sin ^2 35^{\circ}+\cos 15^{\circ} \sin 15^{\circ}-\cos 5^{\circ} \sin 35^{\circ} = $

$\tan 9^{\circ}-\tan 27^{\circ}-\tan 63^{\circ}+\tan 81^{\circ}=$

यदि समीकरणों $x = a \cos(\theta - \alpha)$ और $y = b \cos(\theta - \beta)$ से $\theta$ को विलुप्त किया जाए,तो $\frac{x^2}{a^2} + \frac{y^2}{b^2} - \frac{2xy}{ab} \cos(\alpha - \beta)$ का मान क्या होगा?

समीकरण $\frac{\sin^3 \theta - \cos^3 \theta}{\sin \theta - \cos \theta} - \frac{\cos \theta}{\sqrt{1 + \cot^2 \theta}} - 2 \tan \theta \cot \theta = -1$ सत्य है यदि:

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