If $\frac{\sin(x + y)}{\sin(x - y)} = \frac{a + b}{a - b},$ then $\frac{\tan x}{\tan y}$ is equal to

  • A
    $\frac{b}{a}$
  • B
    $\frac{a}{b}$
  • C
    $ab$
  • D
    None of these

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