If $R$ is the radius of the circumcircle of the $\Delta ABC$ and $\Delta$ is its area,then
- A$R = \frac{a + b + c}{\Delta}$
- B$R = \frac{a + b + c}{4\Delta}$
- C$R = \frac{abc}{4\Delta}$
- D$R = \frac{abc}{\Delta}$
Explore More
Similar Questions
If $I$ is the incentre of $\triangle ABC$ and $P_1, P_2, P_3$ are respectively the radii of the circumcircles of the $\triangle IBC, \triangle ICA$ and $\triangle IAB$,then $P_1 P_2 P_3=$
DifficultAP EAMCET 2018
View SolutionIn $\triangle ABC$, if $a:b:c = 4:5:6$, then the ratio of the circumradius to its inradius is
In $\triangle ABC$,if $a=13 \text{ cm}, b=14 \text{ cm}$ and $c=15 \text{ cm}$,then its circumradius $R$ is:
If $a, b$ and $c$ are the sides of $\triangle ABC$ for which $r_1=8, r_2=12$ and $r_3=24$,then the ordered triad $(a, b, c)=$
In a triangle $ABC$,$a : b : c = 4 : 5 : 6$. The ratio of the radius of the circumcircle to that of the incircle is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo