If $\frac{4 x^3+16 x+7}{\left(x^2+4\right)^2}=\frac{A x+B}{x^2+4}+\frac{C x+D}{\left(x^2+4\right)^2}$,then the number of non-zero values in $A, B, C, D$ is

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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