If $A, B, C$ are the angles of a triangle,then $\frac{\sin A+\sin B+\sin C}{\sin ^2 \frac{A}{2}-\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}-1} =$

  • A
    $-2 \tan \frac{B}{2}$
  • B
    $-2 \cot \frac{B}{2}$
  • C
    $2 \tan \frac{B}{2}$
  • D
    $2 \cot \frac{B}{2}$

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