(C) We are given $|z+4| \geq 3$. By the triangle inequality,we know that $|z+4| = |(z+3) + 1| \leq |z+3| + |1|$. Substituting the given condition,we g

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(C) We are given $|z+4| \geq 3$. By the triangle inequality,we know that $|z+4| = |(z+3) + 1| \leq |z+3| + |1|$. Substituting the given condition,we get $3 \leq |z+3| + 1$. This simplifies to $|z+3| \geq 3 - 1$,which means $|z+3| \geq 2$. Therefore,the smallest value of $|z+3|$ is $2$.

Class 11 Mathematics 4-1.Complex numbers Geometry of complex numbers

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If $z$ is a complex number such that $|z+4| \geq 3$,then the smallest value of $|z+3|$ is

TS EAMCET 2019 All TS EAMCET

A
$3$
B
$1$
C
$2$
D
$0$

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