If x and y are two positive integers such tha | vedclass

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(D) Given $x + 2y = 10$,where $x, y$ are positive integers. Possible pairs $(x, y)$ are: $(8, 1) \implies x^2 y^3 = 8^2 	imes 1^3 = 64$ $(6, 2) \impl

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$70$

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(D) Given $x + 2y = 10$,where $x, y$ are positive integers. Possible pairs $(x, y)$ are: $(8, 1) \implies x^2 y^3 = 8^2 	imes 1^3 = 64$ $(6, 2) \implies x^2 y^3 = 6^2 	imes 2^3 = 36 	imes 8 = 288$ $(4, 3) \implies x^2 y^3 = 4^2 	imes 3^3 = 16 	imes 27 = 432$ $(2, 4) \implies x^2 y^3 = 2^2 	imes 4^3 = 4 	imes 64 = 256$ The maximum value of $x^2 y^3$ is $432$,which occurs when $x = 4$ and $y = 3$. We need to find $x^2 + 2y^3 = 4^2 + 2(3^3) = 16 + 2(27) = 16 + 54 = 70$.

If $x$ and $y$ are two positive integers such that $x + 2y = 10$ and $x^2 y^3$ is maximum,then $x^2 + 2y^3 =$

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