If frac{5 sinh 2x}{7+6 cosh 2x} = frac{3}{2}, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given $\frac{5 \sinh 2x}{7+6 \cosh 2x} = \frac{3}{2}$.Using the identities $\sinh 2x = 2 \sinh x \cosh x$ and $\cosh 2x = 2 \cosh^2 x - 1$,we get:

Vedclass · Accepted Answer

$39$

Vedclass · Answer

(C) Given $\frac{5 \sinh 2x}{7+6 \cosh 2x} = \frac{3}{2}$.Using the identities $\sinh 2x = 2 \sinh x \cosh x$ and $\cosh 2x = 2 \cosh^2 x - 1$,we get:$\frac{5(2 \sinh x \cosh x)}{7+6(2 \cosh^2 x - 1)} = \frac{3}{2}$$\frac{10 \sinh x \cosh x}{12 \cosh^2 x + 1} = \frac{3}{2}$Divide the numerator and denominator by $\cosh^2 x$:$\frac{10 	anh x}{12 + 	ext{sech}^2 x} = \frac{3}{2}$Since $	ext{sech}^2 x = 1 - 	anh^2 x$:$\frac{10 	anh x}{12 + 1 - 	anh^2 x} = \frac{3}{2}$$\frac{10 	anh x}{13 - 	anh^2 x} = \frac{3}{2}$$20 	anh x = 39 - 3 	anh^2 x$$3 	anh^2 x + 20 	anh x = 39$

If $\frac{5 \sinh 2x}{7+6 \cosh 2x} = \frac{3}{2}$,then $3 \tanh^2 x + 20 \tanh x = $

Similar Questions

The expression $\tan 9^{\circ}-\tan 27^{\circ}-\tan 63^{\circ}+\tan 81^{\circ}$ is equal to

If $\frac{\sin (A+B)}{\sin (A-B)}=\frac{\cos (C+D)}{\cos (C-D)}$,then $\tan A \cot B=$

If $x = a \cos^3 \theta$ and $y = b \sin^3 \theta$,then:

If $\frac{\sqrt{2} \sin \alpha}{\sqrt{1+\cos 2 \alpha}}=\frac{1}{7}$ and $\sqrt{\frac{1-\cos 2 \beta}{2}}=\frac{1}{\sqrt{10}}$ where $\alpha, \beta \in (0, \frac{\pi}{2})$,then $\tan (\alpha+2 \beta)$ is equal to

$\sin 20^{\circ} \cdot \sin 40^{\circ} \cdot \sin 60^{\circ} \cdot \sin 80^{\circ}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module