If $y = \frac{1}{x} + \cos 2x$, then $\frac{d^2y}{dx^2}$ is equal to

  • A
    $\frac{2}{x^3} + 4y - \frac{4}{x}$
  • B
    $4y - \frac{4}{x} - \frac{2}{x^3}$
  • C
    $\frac{2}{x^3} + \frac{4}{x} - 4y$
  • D
    $4y - \frac{4}{x} - \frac{1}{x^3}$

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