If y=ae^x+be^{-x}+c, where a, b, c are parame | vedclass

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(C) Given the function: $y = ae^x + be^{-x} + c$ Differentiating with respect to $x$ once: $y^{\prime} = \frac{d}{dx}(ae^x + be^{-x} + c) = ae^x - be^

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$y^{\prime}$

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(C) Given the function: $y = ae^x + be^{-x} + c$ Differentiating with respect to $x$ once: $y^{\prime} = \frac{d}{dx}(ae^x + be^{-x} + c) = ae^x - be^{-x}$ Differentiating again with respect to $x$: $y^{\prime \prime} = \frac{d}{dx}(ae^x - be^{-x}) = ae^x + be^{-x}$ Differentiating a third time with respect to $x$: $y^{\prime \prime \prime} = \frac{d}{dx}(ae^x + be^{-x}) = ae^x - be^{-x}$ Comparing this result with the first derivative, we see that $y^{\prime \prime \prime} = y^{\prime}$.

If $y=ae^x+be^{-x}+c$, where $a, b, c$ are parameters, then $y^{\prime \prime \prime}$ is equal to

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