(A) Given vectors are $r_1 = 2 \hat{x}$ and $r_2 = 2 \hat{y}$.Their sum is $r_1 + r_2 = 2 \hat{x} + 2 \hat{y}$.The magnitude of a vector $A = a \hat{x

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(A) Given vectors are $r_1 = 2 \hat{x}$ and $r_2 = 2 \hat{y}$.Their sum is $r_1 + r_2 = 2 \hat{x} + 2 \hat{y}$.The magnitude of a vector $A = a \hat{x} + b \hat{y}$ is given by $|A| = \sqrt{a^2 + b^2}$.Therefore, $|r_1 + r_2| = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8}$.Simplifying $\sqrt{8}$, we get $\sqrt{4 \times 2} = 2 \sqrt{2}$.

Class 11 Physics 3-1.Vectors Addition and Subtraction of Vectors

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If $r_1=2 \hat{x}$ and $r_2=2 \hat{y}$, where $\hat{x}$ and $\hat{y}$ are unit vectors along the $X$-axis and $Y$-axis respectively, then the magnitude of $r_1+r_2$ is

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A
$2 \sqrt{2}$
B
$2 \sqrt{3}$
C
$3 \sqrt{2}$
D
$\sqrt{3}$

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If $r_1=2 \hat{x}$ and $r_2=2 \hat{y}$, where $\hat{x}$ and $\hat{y}$ are unit vectors along the $X$-axis and $Y$-axis respectively, then the magnitude of $r_1+r_2$ is

Similar Questions

The vectors $\vec{A}$ and $\vec{B}$ are such that $|\vec{A}+\vec{B}|=|\vec{A}-\vec{B}|$. The angle between the two vectors is: (in $^{\circ}$)

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