If f(r) = pi r^2,then lim_{h to 0} frac{f(r + | vedclass

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(B) The given expression $\lim_{h 	o 0} \frac{f(r + h) - f(r)}{h}$ is the definition of the derivative of $f(r)$ with respect to $r$,denoted as $f'(r

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$2\pi r$

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(B) The given expression $\lim_{h 	o 0} \frac{f(r + h) - f(r)}{h}$ is the definition of the derivative of $f(r)$ with respect to $r$,denoted as $f'(r)$ or $\frac{df}{dr}$.Given $f(r) = \pi r^2$.Applying the power rule for differentiation,$\frac{d}{dr}(\pi r^2) = \pi \cdot \frac{d}{dr}(r^2) = \pi \cdot (2r) = 2\pi r$.Therefore,$\lim_{h 	o 0} \frac{f(r + h) - f(r)}{h} = 2\pi r$.

If $f(r) = \pi r^2$,then $\lim_{h \to 0} \frac{f(r + h) - f(r)}{h} = $

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