If f:R to R and g:R to R are defined by f(x) | vedclass

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(C) Given $f(x) = 2x + 3$ and $g(x) = x^2 + 7$.We need to find $x$ such that $g(f(x)) = 8$.First,compute $g(f(x)) = g(2x + 3) = (2x + 3)^2 + 7$.Set th

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$-1, -2$

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(C) Given $f(x) = 2x + 3$ and $g(x) = x^2 + 7$.We need to find $x$ such that $g(f(x)) = 8$.First,compute $g(f(x)) = g(2x + 3) = (2x + 3)^2 + 7$.Set the expression equal to $8$:$(2x + 3)^2 + 7 = 8$$(2x + 3)^2 = 1$Taking the square root on both sides:$2x + 3 = \pm 1$Case $1$: $2x + 3 = 1 \implies 2x = -2 \implies x = -1$.Case $2$: $2x + 3 = -1 \implies 2x = -4 \implies x = -2$.Thus,the values of $x$ are $-1$ and $-2$.

If $f:R \to R$ and $g:R \to R$ are defined by $f(x) = 2x + 3$ and $g(x) = x^2 + 7$,then the values of $x$ such that $g(f(x)) = 8$ are

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