If $y = \frac{e^x + e^{-x}}{e^x - e^{-x}}$,then $\frac{dy}{dx}$ is equal to

  • A
    $\text{sech}^2 x$
  • B
    $\text{cosech}^2 x$
  • C
    $-\text{sech}^2 x$
  • D
    $-\text{cosech}^2 x$

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Similar Questions

Suppose that $h(x) = f(x) \cdot g(x)$ and $F(x) = f(g(x))$,where $f(2) = 3$,$g(2) = 5$,$g'(2) = 4$,$f'(2) = -2$,and $f'(5) = 11$. Then:

Find the derivative of $f(x) = 1 + x + x^{2} + x^{3} + \dots + x^{50}$ at $x = 1$.

$\frac{d}{d x}\left(\frac{x+5}{(x+1)^2(x+2)}\right)=$

If $y = \sin(2 \sin^{-1} x)$, then $\frac{dy}{dx} = \dots$

If $f(x)=3 e^{x^2}$ then $f^{\prime}(x)-2 x f(x)+\frac{1}{3} f(0)-f^{\prime}(0)=$

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