If y = a{e^x} + b{e^{-x}} + c where a, b, c a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the equation $y = a{e^x} + b{e^{-x}} + c$. First derivative: $y' = \frac{d}{dx}(a{e^x} + b{e^{-x}} + c) = a{e^x} - b{e^{-x}}$. Second deriva

Vedclass · Accepted Answer

$y'$

Vedclass · Answer

(B) Given the equation $y = a{e^x} + b{e^{-x}} + c$. First derivative: $y' = \frac{d}{dx}(a{e^x} + b{e^{-x}} + c) = a{e^x} - b{e^{-x}}$. Second derivative: $y'' = \frac{d}{dx}(a{e^x} - b{e^{-x}}) = a{e^x} + b{e^{-x}}$. Third derivative: $y''' = \frac{d}{dx}(a{e^x} + b{e^{-x}}) = a{e^x} - b{e^{-x}}$. Comparing this with the first derivative,we see that $y''' = y'$.

If $y = a{e^x} + b{e^{-x}} + c$ where $a, b, c$ are parameters,then $y''' = $

Similar Questions

Find the second order derivative of the function $f(x) = x \cdot \cos x$.

If $y = (1 - x^2) \operatorname{Tanh}^{-1} x$, then $\frac{d^2 y}{d x^2} = $

If $f(x) = \sin x + \cos x$, then $f\left(\frac{\pi}{4}\right) f^{(iv)}\left(\frac{\pi}{4}\right)$ is equal to

If $y = 1 - x + \frac{x^2}{2!} - \frac{x^3}{3!} + \frac{x^4}{4!} - \dots$,then $\frac{d^2y}{dx^2} = $

If $y=A \cos n x+B \sin n x$,then $y_2+n^2 y$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module