જો ${z^2} = \frac{{x^{1/2} + y^{1/2}}}{{x^{1/3} + y^{1/3}}}$ હોય,તો $x\frac{{\partial z}}{{\partial x}} + y\frac{{\partial z}}{{\partial y}} = $

  • A
    $\frac{z}{6}$
  • B
    $\frac{z}{3}$
  • C
    $\frac{z}{2}$
  • D
    $\frac{z}{12}$

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