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(B) For the Lyman series,the wave number $\bar{
u}$ is given by the Rydberg formula:$\bar{
u} = \frac{1}{\lambda} = R \left( \frac{1}{n_1^2} - \frac

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$\frac{3R}{4}$

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(B) For the Lyman series,the wave number $\bar{
u}$ is given by the Rydberg formula:$\bar{
u} = \frac{1}{\lambda} = R \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} ight)$where $n_1 = 1$ and $n_2 = 2, 3, 4, \dots$For the first line of the Lyman series,we take $n_1 = 1$ and $n_2 = 2$.Substituting these values into the formula:$\bar{
u} = R \left( \frac{1}{1^2} - \frac{1}{2^2} ight)$$\bar{
u} = R \left( 1 - \frac{1}{4} ight)$$\bar{
u} = R \left( \frac{3}{4} ight) = \frac{3R}{4}$

If $R$ is the Rydberg constant for hydrogen,the wave number of the first line in the Lyman series will be

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