If (a, 1/a),(b, 1/b),(c, 1/c),and (d, 1/d) ar | vedclass

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(C) Let the equation of the circle be $x^2 + y^2 = r^2$. Given the radius $r = 4$,the equation is $x^2 + y^2 = 16$.Since the points $(t, 1/t)$ lie on

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(C) Let the equation of the circle be $x^2 + y^2 = r^2$. Given the radius $r = 4$,the equation is $x^2 + y^2 = 16$.Since the points $(t, 1/t)$ lie on the circle,they must satisfy the equation:$t^2 + (1/t)^2 = 16$Multiplying by $t^2$,we get $t^4 - 16t^2 + 1 = 0$.This is a biquadratic equation in $t$ where the roots are $a, b, c, d$.The product of the roots of the equation $t^4 + 0t^3 - 16t^2 + 0t + 1 = 0$ is given by the constant term divided by the leading coefficient.Thus,$abcd = 1/1 = 1$.

If $(a, 1/a)$,$(b, 1/b)$,$(c, 1/c)$,and $(d, 1/d)$ are four distinct points on a circle of radius $4$ units,then $abcd$ is equal to

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