If a point $(a, a)$ lies between the lines $|x+y|=4$,then

The distance of the point $(2, 5)$ from the line $3x + y + 4 = 0$,measured parallel to the line $3x - 4y + 8 = 0$,is

The distance between the lines $4x + 3y = 11$ and $8x + 6y = 15$ is:

Find the distance between the lines $3x + 4y + 7 = 0$ and $3x + 4y + 22 = 0$.

Find the distance of the point $(-1, 1)$ from the line $12(x + 6) = 5(y - 2)$. (in $units$)

The line $L$ is given by $\frac{x}{5} + \frac{y}{b} = 1$ and passes through the point $(13, 32)$. The line $K$ is parallel to $L$ and has the equation $\frac{x}{c} + \frac{y}{3} = 1$. Then the distance between $L$ and $K$ is