If an AC main supply is given to be 220,V,the | vedclass

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(A) The given $AC$ voltage is the $rms$ value,so $E_{rms} = 220\,V$.The peak voltage $E_{0}$ is related to $E_{rms}$ by the formula $E_{rms} = \frac{E

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$198$

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(A) The given $AC$ voltage is the $rms$ value,so $E_{rms} = 220\,V$.The peak voltage $E_{0}$ is related to $E_{rms}$ by the formula $E_{rms} = \frac{E_{0}}{\sqrt{2}}$,which gives $E_{0} = E_{rms} 	imes \sqrt{2} = 220\sqrt{2}\,V$.The average $emf$ over a positive half cycle is given by the formula $E_{avg} = \frac{2}{\pi} E_{0}$.Substituting the value of $E_{0}$,we get $E_{avg} = \frac{2}{\pi} 	imes 220\sqrt{2}$.Using $\pi \approx 3.14$ and $\sqrt{2} \approx 1.414$,we get $E_{avg} = \frac{2}{3.14} 	imes 220 	imes 1.414 \approx 0.637 	imes 311.13 \approx 198.18\,V$.Rounding to the nearest integer,the average $emf$ is $198\,V$.

If an $AC$ main supply is given to be $220\,V$,the average $emf$ during a positive half cycle will be.....$V$.

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