If current in an electric bulb changes by 1%, | vedclass

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(B) The power $P$ consumed by an electric bulb is given by the formula $P = i^2R$,where $i$ is the current and $R$ is the resistance of the bulb.Assum

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$2$

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(B) The power $P$ consumed by an electric bulb is given by the formula $P = i^2R$,where $i$ is the current and $R$ is the resistance of the bulb.Assuming the resistance $R$ remains constant,we can use the method of relative errors:$\frac{\Delta P}{P} = 2 \frac{\Delta i}{i}$.To find the percentage change,we multiply both sides by $100$:$\left( \frac{\Delta P}{P} 	imes 100 ight) = 2 	imes \left( \frac{\Delta i}{i} 	imes 100 ight)$.Given that the percentage change in current is $1\%$,we have:$\% 	ext{ change in power} = 2 	imes 1\% = 2\%$.Therefore,the power will change by $2\%$.

If current in an electric bulb changes by $1\%$,then the power will change by ............ $\%$

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