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(D) The kinetic energy $(K.E.)$ of a satellite in an orbit of radius $r$ is given by $K.E. = \frac{G M m}{2 r}$.As $r$ decreases,the denominator decre

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Increases and potential energy decreases

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(D) The kinetic energy $(K.E.)$ of a satellite in an orbit of radius $r$ is given by $K.E. = \frac{G M m}{2 r}$.As $r$ decreases,the denominator decreases,so the kinetic energy $(K.E.)$ increases.The potential energy $(P.E.)$ of the satellite is given by $P.E. = -\frac{G M m}{r}$.As $r$ decreases,the magnitude of the negative value increases,meaning the potential energy becomes more negative,which signifies a decrease in potential energy.Therefore,kinetic energy increases and potential energy decreases.

If the radius of an orbiting satellite is decreased,then its kinetic energy

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