In a satellite,if the time of revolution is $T$,then the potential energy $(PE)$ is proportional to ..........

  • A
    $T^{1/3}$
  • B
    $T^3$
  • C
    $T^{-2/3}$
  • D
    $T^{-4/3}$

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Similar Questions

Match the following columns.
$A$. Potential energy of satellite$I$. Positive
$B$. Total energy of satellite$II$. Negative
$C$. Kinetic energy of satellite$III$. Zero
$D$. Gravitational potential energy of satellite at infinity$IV$. Infinity

$A$ particle of mass $m$ moves in a horizontal circle of radius $r$ under the influence of a centripetal force given by $F = -k/r^2$,where $k$ is a constant. Calculate the total energy of the particle.

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The figure shows the variation of energy with the orbit radius of a body in circular planetary motion. Find the correct statement about the curves $A, B$ and $C$.

If the radius of an orbiting satellite is decreased,then its kinetic energy

Choose the correct alternative:
$(a)$ If the zero of potential energy is at infinity,the total energy of an orbiting satellite is negative of its kinetic/potential energy.
$(b)$ The energy required to launch an orbiting satellite out of Earth's gravitational influence is more/less than the energy required to project a stationary object at the same height (as the satellite) out of Earth's influence.

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