If the arithmetic mean of the following frequency distribution is $50$,find the values of $f_1$ and $f_2$.
ClassFrequency
$0 - 20$$17$
$20 - 40$$f_1$
$40 - 60$$32$
$60 - 80$$f_2$
$80 - 100$$19$
Total$120$

  • A
    $f_1 = 27, f_2 = 35$
  • B
    $f_1 = 30, f_2 = 22$
  • C
    $f_1 = 28, f_2 = 24$
  • D
    $f_1 = 32, f_2 = 20$

Explore More

Similar Questions

The mean and variance of the marks obtained by $n$ students in a test are $10$ and $4$ respectively. Later,the marks of one of the students is increased from $8$ to $12$. If the new mean of the marks is $10.2$,then their new variance is equal to:

Let the mean and the variance of $20$ observations $x_{1}, x_{2}, \ldots, x_{20}$ be $15$ and $9$,respectively. For $\alpha \in R$,if the mean of $(x_{1}+\alpha)^{2}, (x_{2}+\alpha)^{2}, \ldots, (x_{20}+\alpha)^{2}$ is $178$,then the square of the maximum value of $\alpha$ is equal to $...........$

Find the range of the given numbers: $10, 8, 12, 11, 14, 9, 6$.

Consider the following data:
Daily wage (Rs.)$30$-$40$$40$-$50$$50$-$60$$60$-$70$$70$-$80$$80$-$90$
No. of workers$17$$28$$21$$15$$13$$6$

The coefficient of variation of the above distribution of wages,if its standard deviation is $14.72$,is

If both mean and variance of $50$ observations $x_1, x_2, \ldots, x_{50}$ are equal to $16$ and $256$ respectively,then the mean of $(x_1-5)^2, (x_2-5)^2, \ldots, (x_{50}-5)^2$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo