If the conjugate of (x+iy)(1-2i) is (1+i),the | vedclass

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(B) Given that the conjugate of $(x+iy)(1-2i)$ is $(1+i)$.Let $z = (x+iy)(1-2i)$.Then $\bar{z} = 1+i$.Since $\bar{z} = (x-iy)(1+2i)$,we have $(x-iy)(1

Vedclass · Accepted Answer

$x+iy=\frac{1-i}{1-2i}$

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(B) Given that the conjugate of $(x+iy)(1-2i)$ is $(1+i)$.Let $z = (x+iy)(1-2i)$.Then $\bar{z} = 1+i$.Since $\bar{z} = (x-iy)(1+2i)$,we have $(x-iy)(1+2i) = 1+i$.Therefore,$x-iy = \frac{1+i}{1+2i}$.Taking the conjugate of both sides,we get $\overline{x-iy} = \overline{\left(\frac{1+i}{1+2i}\right)}$.This simplifies to $x+iy = \frac{1-i}{1-2i}$.

If the conjugate of $(x+iy)(1-2i)$ is $(1+i)$,then

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