If the emf of an AC source is given by E = 6 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given emf is $E = 6 \sin \omega t + 4 \sin 2 \omega t 	ext{ V}$.For a non-sinusoidal periodic waveform $E = E_1 \sin \omega t + E_2 \sin 2 \o

Vedclass · Accepted Answer

$\sqrt{26} 	ext{ V}$

Vedclass · Answer

(B) The given emf is $E = 6 \sin \omega t + 4 \sin 2 \omega t 	ext{ V}$.For a non-sinusoidal periodic waveform $E = E_1 \sin \omega t + E_2 \sin 2 \omega t + \dots$,the rms value is given by $E_{	ext{rms}} = \sqrt{\frac{E_1^2 + E_2^2 + \dots}{2}}$.Here,$E_1 = 6 	ext{ V}$ and $E_2 = 4 	ext{ V}$.Substituting these values into the formula:$E_{	ext{rms}} = \sqrt{\frac{6^2 + 4^2}{2}}$$E_{	ext{rms}} = \sqrt{\frac{36 + 16}{2}}$$E_{	ext{rms}} = \sqrt{\frac{52}{2}}$$E_{	ext{rms}} = \sqrt{26} 	ext{ V}$.Thus,the rms value of the emf is $\sqrt{26} 	ext{ V}$.

$(A) \ x_0 \sin \omega t$	$(i) \ x_0$
$(B) \ x_0 \sin \omega t \cos \omega t$	$(ii) \ \frac{x_0}{\sqrt{2}}$
$(C) \ x_0 \sin \omega t + x_0 \cos \omega t$	$(iii) \ \frac{x_0}{2 \sqrt{2}}$

If the emf of an $AC$ source is given by $E = 6 \sin \omega t + 4 \sin 2 \omega t \text{ V}$,then the rms value of the emf is

Similar Questions

In an $AC$ circuit,the peak value of voltage is $423 \ V$. Its effective voltage is .......... $V$.

What is $rms$ (root mean square) value? Write the formula of $rms$ current for an alternating current.

$A$ $110 \, V$ $d.c.$ heater is used on an $a.c.$ source,such that the heat produced is the same as it produces when connected to $110 \, V$ $d.c.$ in the same time intervals. What would be the $r.m.s.$ value of the alternating voltage?

What is the approximate percentage value of the ratio of maximum voltage to its rms value in an $LCR$ $AC$ circuit (in $\%$)?

Match the following current $\text{r.m.s.}$ values:
$(A) \ x_0 \sin \omega t$ $(i) \ x_0$
$(B) \ x_0 \sin \omega t \cos \omega t$ $(ii) \ \frac{x_0}{\sqrt{2}}$
$(C) \ x_0 \sin \omega t + x_0 \cos \omega t$ $(iii) \ \frac{x_0}{2 \sqrt{2}}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module