If the equation of the circle lying in the first quadrant,touching both the coordinate axes and the line $\frac{x}{3}+\frac{y}{4}=1$ is $(x-c)^2+(y-c)^2=c^2$,then $c=$

  • A
    $1$ or $4$
  • B
    $2$ or $3$
  • C
    $1$ or $6$
  • D
    $2$ or $5$

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