(D) The time period $T$ of the second's hand in a clock is $60 \, s$.The angular velocity $\omega$ is given by $\omega = \frac{2\pi}{T} = \frac{2 \tim

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$0.1047 \, rad/s, 0.00314 \, m/s$

(D) The time period $T$ of the second's hand in a clock is $60 \, s$.The angular velocity $\omega$ is given by $\omega = \frac{2\pi}{T} = \frac{2 \times 3.14159}{60} \approx 0.1047 \, rad/s$.The length of the hand $r = 3 \, cm = 3 \times 10^{-2} \, m$.The linear velocity $v$ of the tip is given by $v = \omega r$.Substituting the values: $v = 0.1047 \times 3 \times 10^{-2} = 0.00314 \, m/s$.

Class 11 Physics 3-2.Motion in Plane Kinematics Circular Motion (Uniform Angular Accelaration)

Easy

If the length of the second's hand in a stop clock is $3 \, cm$,the angular velocity and linear velocity of the tip are:

A
$0.2047 \, rad/s, 0.0314 \, m/s$
B
$0.2547 \, rad/s, 0.314 \, m/s$
C
$0.1472 \, rad/s, 0.06314 \, m/s$
D
$0.1047 \, rad/s, 0.00314 \, m/s$

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3-2.Motion in Plane

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Kinematics Circular Motion (Uniform Angular Accelaration)

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If the length of the second's hand in a stop clock is $3 \, cm$,the angular velocity and linear velocity of the tip are:

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