If the number of turns in the coil of a moving coil galvanometer decreases, the resistance of the galvanometer,

$A$ galvanometer coil has a resistance of $10 \Omega$ and the meter shows full scale deflection for a current of $2 \text{ mA}$. What resistance needs to be connected to convert the meter into a voltmeter of range $0$ to $18 \text{ V}$ (in $\Omega$)?

$A$ galvanometer having coil resistance $10 \ \Omega$ shows a full scale deflection for a current of $3 \ mA$. For it to measure a current of $8 \ A$,the value of the shunt should be:

What will be the resistance of the shunt when $5 \%$ of the main current is passed through a galvanometer of resistance $G$?

The maximum current that can be measured by a galvanometer of resistance $40 \,\Omega$ is $10 \,mA$. It is converted into a voltmeter that can read up to $50 \,V$. The resistance to be connected in series with the galvanometer is ... (in $\Omega$)

An ammeter gives full-scale deflection when a current of $2 \, A$ flows through it. The resistance of the ammeter is $12 \, \Omega$. If the same ammeter is to be used for measuring a maximum current of $5 \, A$,then the ammeter must be connected with a resistance of: