(A) The given equation of the pair of straight lines is $xy-x+y-1=0$. Factorizing the expression: $x(y-1)+1(y-1)=0$,which gives $(x+1)(y-1)=0$. This r

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(A) The given equation of the pair of straight lines is $xy-x+y-1=0$. Factorizing the expression: $x(y-1)+1(y-1)=0$,which gives $(x+1)(y-1)=0$. This represents two lines: $L_1: x+1=0$ and $L_2: y-1=0$. The intersection point of these two lines is $(-1, 1)$. Since the line $x+ky-3=0$ is concurrent with these lines,it must pass through the point $(-1, 1)$. Substituting $(-1, 1)$ into the line equation: $-1 + k(1) - 3 = 0$. $k - 4 = 0$,which implies $k = 4$.

Class 11 Mathematics Pair of straight lines Bisectors of the angle between the lines, Point of intersection of the lines

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If the pair of straight lines $xy-x+y-1=0$ and the line $x+ky-3=0$ are concurrent,then the value of $k$ is equal to

MHT CET 2025 All MHT CET

A
$4$
B
$3$
C
$-1$
D
$2$

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Pair of straight lines

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Bisectors of the angle between the lines, Point of intersection of the lines

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If the pair of straight lines $xy-x+y-1=0$ and the line $x+ky-3=0$ are concurrent,then the value of $k$ is equal to

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