If the position vectors of $A, B$ and $C$ are respectively $2 \hat{i}-\hat{j}+\hat{k}, \hat{i}-3 \hat{j}-5 \hat{k}$ and $3 \hat{i}-4 \hat{j}-4 \hat{k}$,then $\cos ^2 A$ is equal to

  • A
    $0$
  • B
    $\frac{6}{41}$
  • C
    $\frac{35}{41}$
  • D
    $1$

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