If the rate of increase of the surface area of a spherical balloon is $5 \text{ cm}^2/\text{sec}$ and the rate of increase of its volume is $10 \text{ cm}^3/\text{sec}$, then the radius of the balloon at that instant is... (in $\text{ cm}$)

If the surface area of a spherical bubble is increasing at the rate of $4 \text{ cm}^2/\text{sec}$,then the rate of change in its volume (in $\text{cm}^3/\text{sec}$) when its radius is $8 \text{ cm}$ is:

$A$ rod $AB$,$13 \text{ feet}$ long,moves with its ends $A$ and $B$ on two perpendicular lines $OX$ and $OY$ respectively. When $A$ is $5 \text{ feet}$ from $O$,it is moving away at the rate of $3 \text{ feet/sec}$. At this instant,$B$ is moving at the rate of:

$A$ spherical iron ball of radius $10 \, cm$ is coated with a layer of ice of uniform thickness that melts at a rate of $50 \, cm^3/min$. When the thickness of the ice is $5 \, cm$,then the rate at which the thickness (in $cm/min$) of ice decreases is

What will be the rate of change of the volume of a sphere with radius $r$,with respect to its diameter?

If $y = x - x^2$,then the rate of change of $y^2$ with respect to $x^2$ at $x = 2$ is