If the solubility product of $BaSO_4$ is $1.5 \times 10^{-9}$ in water,its solubility in moles per litre is

  • A
    $1.5 \times 10^{-9}$
  • B
    $3.9 \times 10^{-5}$
  • C
    $7.5 \times 10^{-5}$
  • D
    $1.5 \times 10^{-5}$

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