If the sum and the product of the mean and variance of a binomial distribution are $24$ and $128$ respectively,then the probability of one or two successes is:

  • A
    $\frac{33}{2^{32}}$
  • B
    $\frac{33}{2^{29}}$
  • C
    $\frac{33}{2^{28}}$
  • D
    $\frac{33}{2^{27}}$

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