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(A) conditional statement $A 	o B$ is false only when $A$ is true and $B$ is false.Here, $A = [(p \lor q) \land (q 	o r) \land (\sim r)]$ and $B = (

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$(F, T)$

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(A) conditional statement $A 	o B$ is false only when $A$ is true and $B$ is false.Here, $A = [(p \lor q) \land (q 	o r) \land (\sim r)]$ and $B = (p \land q)$.Since $B = (p \land q)$ is false, at least one of $p$ or $q$ must be false.Since $A$ is true, all components $(p \lor q)$, $(q 	o r)$, and $(\sim r)$ must be true.From $(\sim r) = T$, we get $r = F$.Substitute $r = F$ into $(q 	o r) = T$, which becomes $(q 	o F) = T$. This implies $q = F$.Now substitute $q = F$ into $(p \lor q) = T$, which becomes $(p \lor F) = T$. This implies $p = T$.Check consistency: $p=T, q=F, r=F$. $B = (T \land F) = F$ (Correct).Now calculate truth values:$p 	o q = T 	o F = F$.$q 	o p = F 	o T = T$.Thus, the truth values are $(F, T)$.

If the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is false, then the truth values of $p \to q$ and $q \to p$ are respectively...

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