If the value of potential in an $AC$ circuit is $10 \ V$,then the peak value of potential is

An alternating e.m.f. is given as $e = e_0 \sin \omega t$. In what time will the e.m.f. have half its maximum value if $e$ starts from zero?
$(T = \text{time period}, \sin 30^{\circ} = \cos 60^{\circ} = 0.5)$

$A$ resistance of $20 \Omega$ is connected to a source of an alternating potential $V = 200 \sin (10 \pi t)$. If $t$ is the time taken by the current to change from the peak value to rms value,then $t$ is (in seconds).

Both alternating current and direct current are measured in amperes. But how is the ampere defined for an alternating current?

The ratio of the peak value to the root mean square (r.m.s.) value of an alternating current is:

In general,in an alternating current circuit: