If the vector a = 2hat{i} + 3hat{j} + 6hat{k} | vedclass

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(B) Given that $a = 2\hat{i} + 3\hat{j} + 6\hat{k}$.First,calculate the magnitude of vector $a$:$|a| = \sqrt{2^2 + 3^2 + 6^2} = \sqrt{4 + 9 + 36} = \s

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$\pm 3(2\hat{i} + 3\hat{j} + 6\hat{k})$

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(B) Given that $a = 2\hat{i} + 3\hat{j} + 6\hat{k}$.First,calculate the magnitude of vector $a$:$|a| = \sqrt{2^2 + 3^2 + 6^2} = \sqrt{4 + 9 + 36} = \sqrt{49} = 7$.Since $a$ and $b$ are collinear,$b$ can be written as $b = k a$ for some scalar $k$.Given $|b| = 21$,we have $|k a| = 21$,which implies $|k| |a| = 21$.Substituting $|a| = 7$,we get $|k| 	imes 7 = 21$,so $|k| = 3$,which means $k = \pm 3$.Therefore,$b = \pm 3(2\hat{i} + 3\hat{j} + 6\hat{k})$.

If the vector $a = 2\hat{i} + 3\hat{j} + 6\hat{k}$ and $b$ are collinear and $|b| = 21$,then $b$ is equal to:

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