If the transverse and conjugate axes of a hyp | vedclass

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(B) The standard equation of a hyperbola is $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$.Given that the transverse axis $(2a)$ and conjugate axis $(2b)$ ar

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$\sqrt{2}$

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(B) The standard equation of a hyperbola is $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$.Given that the transverse axis $(2a)$ and conjugate axis $(2b)$ are equal,we have $2a = 2b$,which implies $a = b$.Substituting $a = b$ into the eccentricity formula $e = \sqrt{1 + \frac{b^2}{a^2}}$,we get:$e = \sqrt{1 + \frac{a^2}{a^2}} = \sqrt{1 + 1} = \sqrt{2}$.Thus,the eccentricity of a rectangular hyperbola is $\sqrt{2}$.

If the transverse and conjugate axes of a hyperbola are equal,then its eccentricity is

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