In triangle ABC,m angle B = 90^circ,AB = 4 an | vedclass

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(B) In a right-angled triangle,the radius $r$ of the incircle is given by the formula $r = \frac{AB + BC - AC}{2}$.First,we find the hypotenuse $AC$ u

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$1$

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(B) In a right-angled triangle,the radius $r$ of the incircle is given by the formula $r = \frac{AB + BC - AC}{2}$.First,we find the hypotenuse $AC$ using the Pythagorean theorem: $AC = \sqrt{AB^2 + BC^2} = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5$.Now,substitute the values into the formula: $r = \frac{4 + 3 - 5}{2} = \frac{7 - 5}{2} = \frac{2}{2} = 1$.Therefore,the radius of the incircle is $1$.

In $\triangle ABC$,$m \angle B = 90^\circ$,$AB = 4$ and $BC = 3$. Find the radius of the incircle of the triangle.

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