In a $p-n-p$ transistor working as a common base amplifier, when the current gain is $0.96$ and emitter current is $7.2 \,mA$, the base current is (in $\,mA$)

$A$ transistor is operated in common emitter configuration at $V_C = 2 \, V$ such that a change in the base current from $100 \, \mu A$ to $300 \, \mu A$ produces a change in the collector current from $10 \, mA$ to $20 \, mA$. The current gain is

For a transistor amplifier,the power gain and voltage gain are $7.5$ and $2.5$ respectively. The value of the current gain will be:

Identify the terminals of this $BJT$ and the type of $BJT$ $(NPN$ or $PNP)$. The multimeter is set to diode test mode (indicated by the symbol),and the black probe is connected to the $COM$ port while the red probe is connected to the $V\Omega$ port. Based on the connections shown in the image,determine the terminal configuration (from left to right) and the transistor type.

In a $PNP$ transistor working as a common-base amplifier,current gain is $0.96$ and emitter current is $7.2 \, mA$. The base current is.....$mA$

In a common emitter configuration with suitable bias,it is given that $R_L$ is the load resistance and $R_{BE}$ is the small signal dynamic resistance (input side). Then,the voltage gain,current gain,and power gain are given,respectively,by: [$\beta$ is the current gain,$I_B$,$I_C$,$I_E$ are respectively base,collector,and emitter currents]