In a $\Delta ABC$, if $\angle C = 90^{\circ}$, $r$ and $R$ are the inradius and circumradius of the $\Delta ABC$ respectively, then $2(r+R)$ is equal to

  • A
    $b+c$
  • B
    $c+a$
  • C
    $a+b$
  • D
    $a+b+c$

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