In a binomial distribution, the probability o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given that the probability of success is $p = \frac{1}{4}$.Then, the probability of failure is $q = 1 - p = 1 - \frac{1}{4} = \frac{3}{4}$.The sta

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(D) Given that the probability of success is $p = \frac{1}{4}$.Then, the probability of failure is $q = 1 - p = 1 - \frac{1}{4} = \frac{3}{4}$.The standard deviation $(SD)$ of a binomial distribution is given by $\sqrt{npq} = 3$.Squaring both sides, we get $npq = 9$.Substituting the values of $p$ and $q$:$n 	imes \frac{1}{4} 	imes \frac{3}{4} = 9$$n 	imes \frac{3}{16} = 9$$n = 9 	imes \frac{16}{3} = 3 	imes 16 = 48$.The mean of a binomial distribution is given by $np$.Mean $= 48 	imes \frac{1}{4} = 12$.

In a binomial distribution, the probability of success is $\frac{1}{4}$ and the standard deviation is $3$. Then, its mean is

Similar Questions

Which one of the following is correct?

The refracting angle of a prism is $A$ and the refractive index of the material of the prism is $\cot(A/2)$. Then the angle of minimum deviation is

The gas that cannot be collected over water is

In a bicycle,the radius of the rear wheel is twice the radius of the front wheel. If $r_F$ and $r_r$ are the radii,and $v_F$ and $v_r$ are the velocities of the highest points of the front and rear wheels respectively,then:

The binding energy per nucleon of $^{16}O$ is $7.97 \, MeV$ and that of $^{17}O$ is $7.75 \, MeV$. The energy (in $MeV$) required to remove a neutron from $^{17}O$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module