In a class of 35 students,24 like to play cri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $X$ be the set of students who like to play cricket and $Y$ be the set of students who like to play football.Given that each student likes to

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) Let $X$ be the set of students who like to play cricket and $Y$ be the set of students who like to play football.Given that each student likes to play at least one game,we have $n(X \cup Y) = 35$.We are given $n(X) = 24$ and $n(Y) = 16$.Using the formula $n(X \cup Y) = n(X) + n(Y) - n(X \cap Y)$,we have:$35 = 24 + 16 - n(X \cap Y)$$35 = 40 - n(X \cap Y)$$n(X \cap Y) = 40 - 35 = 5$.Thus,$5$ students like to play both cricket and football.

In a class of $35$ students,$24$ like to play cricket and $16$ like to play football. Also,each student likes to play at least one of the two games. How many students like to play both cricket and football?

Similar Questions

The probability of choosing at random a number that is divisible by $6$ or $8$ from among $1$ to $90$ is equal to

$A$ and $B$ are non-singleton sets and $n(A \times B) = 35$. If $B \subset A$,then ${}^{n(A)}C_{n(B)}$ is equal to

Let $S$ be the set of the first $11$ natural numbers. Then the number of elements in $A = \{B \subseteq S : n(B) \ge 2 \text{ and the product of all elements of } B \text{ is even}\}$ is . . . . . . .

The smallest set $A$ such that $A \cup \{1, 2\} = \{1, 2, 3, 5, 9\}$ is

Let $A = \{x : x \in R, |x| < 1\};$ $B = \{x : x \in R, |x - 1| \ge 1\}$ and $A \cup B = R - D,$ then the set $D$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module