In a medium, the phase difference between two | vedclass

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(C) Given: Phase difference $\phi = \frac{\pi}{5} 	ext{ rad}$, Frequency $f = 25 	ext{ Hz}$, Velocity $v = 75 	ext{ m/s}$.First, calculate the wave

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$0.3$

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(C) Given: Phase difference $\phi = \frac{\pi}{5} 	ext{ rad}$, Frequency $f = 25 	ext{ Hz}$, Velocity $v = 75 	ext{ m/s}$.First, calculate the wavelength $\lambda$ using the formula $\lambda = \frac{v}{f}$:$\lambda = \frac{75 	ext{ m/s}}{25 	ext{ Hz}} = 3 	ext{ m}$.The relationship between phase difference $\phi$ and path difference $x$ is given by:$\phi = \frac{2\pi}{\lambda} x$.Substituting the known values:$\frac{\pi}{5} = \frac{2\pi}{3} x$.Solving for $x$:$x = \frac{\pi}{5} 	imes \frac{3}{2\pi} = \frac{3}{10} 	ext{ m} = 0.3 	ext{ m}$.

In a medium, the phase difference between two particles separated by a distance $x$ is $\frac{\pi}{5} \text{ rad}$. If the frequency of the oscillation of particles is $25 \text{ Hz}$ and the velocity of propagation of the wave is $75 \text{ m/s}$, then the value of $x$ is (in $\text{ m}$)

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