In a particular section of Class $IX,$ $40$ students were asked about the months of their birth and the following graph was prepared for the data so obtained:
Observe the bar graph given above and answer the following questions:
$(i)$ How many students were born in the month of November?
$(ii)$ In which month were the maximum number of students born?

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(N/A) Note that the variable here is the 'month of birth',and the value of the variable is the 'Number of students born'.
$(i)$ By observing the bar graph,the height of the bar corresponding to the month of November is $4$. Thus,$4$ students were born in the month of November.
$(ii)$ By observing the bar graph,the tallest bar corresponds to the month of August,which has a height of $6$. Thus,the maximum number of students were born in the month of August.

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Similar Questions

The runs scored by two teams $A$ and $B$ on the first $60$ balls in a cricket match are given below:
Number of balls Teams $A$ Teams $B$
$1-6$ $2$ $5$
$7-12$ $1$ $6$
$13-18$ $8$ $2$
$19-24$ $9$ $10$
$25-30$ $4$ $5$
$31-36$ $5$ $6$
$37-42$ $6$ $3$
$43-48$ $10$ $4$
$49-54$ $6$ $8$
$55-60$ $2$ $10$

Represent the data of both the teams on the same graph by frequency polygons.
[Hint : First make the class intervals continuous.]

Let us consider the following frequency distribution table which gives the weights of $38$ students of a class:
Weights (in $kg$) Number of students
$31-35$ $9$
$36-40$ $5$
$41-45$ $14$
$46-50$ $3$
$51-55$ $1$
$56-60$ $2$
$61-65$ $2$
$66-70$ $1$
$71-75$ $1$
Total $38$

If two new students of weights $35.5\, kg$ and $40.5\, kg$ are admitted to this class,how should the frequency distribution table be adjusted to include them?

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Give one example of a situation in which $(i)$ the mean is not an appropriate measure of central tendency but the median is an appropriate measure of central tendency.

Thirty children were asked about the number of hours they watched $TV$ programmes in the previous week. The results were found as follows:
$\begin{array}{rrrrrrrrrr}1 & 6 & 2 & 3 & 5 & 12 & 5 & 8 & 4 & 8 \\ 10 & 3 & 4 & 12 & 2 & 8 & 15 & 1 & 17 & 6 \\ 3 & 2 & 8 & 5 & 9 & 6 & 8 & 7 & 14 & 12\end{array}$
$(i)$ Make a grouped frequency distribution table for this data,taking class width $5$ and one of the class intervals as $5-10$.
$(ii)$ How many children watched television for $15$ or more hours a week?

The following table gives the distribution of students of two sections according to the marks obtained by them:
Marks (Section $A$) Frequency (Section $A$) Marks (Section $B$) Frequency (Section $B$)
$0-10$ $3$ $0-10$ $5$
$10-20$ $9$ $10-20$ $19$
$20-30$ $17$ $20-30$ $15$
$30-40$ $12$ $30-40$ $10$
$40-50$ $9$ $40-50$ $1$

Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons,compare the performance of the two sections.

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